Here is a Python solution to the CS50 Tideman problem:
// Get the names of the candidates Candidate candidates[num_candidates]; for (int i = 0; i < num_candidates; i++) { printf("Enter candidate %d: ", i+1); scanf("%s", candidates[i].name); candidates[i].votes = 0; } Cs50 Tideman Solution
char* tideman(Candidate candidates[], int num_candidates, Voter voters[], int num_voters) { // Count first-choice votes for (int i = 0; i < num_candidates; i++) { candidates[i].votes = 0; } for (int i = 0; i < num_voters; i++) { for (int j = 0; j < num_candidates; j++) { if (strcmp(voters[i].preferences[j], "") != 0) { for (int k = 0; k < num_candidates; k++) { if (strcmp(candidates[k].name, voters[i].preferences[j]) == 0) { candidates[k].votes++; } } break; } } } Here is a Python solution to the CS50
// Find the new minimum votes min_votes = MAX_VOTERS; for (int i = 0; i < num_candidates; i++) { if (candidates[i].votes >= 0 && candidates[i]. for (int i = 0
// Run the Tideman algorithm char* winner = tideman(candidates, num_candidates, voters, num_voters);
# Get the ranked preferences for each voter pairs = [] for i in range(num_voters): voter_preferences = [] print(f"\nEnter the ranked preferences for voter {i+1}:") for j in range(num_candidates): preference = input(f"Enter preference {j+1}: ") voter_preferences.append(preference) pairs.append(voter_preferences)
int main() { // Get the number of candidates and voters int num_candidates, num_voters; printf("Enter the number of candidates: "); scanf("%d", &num_candidates); printf("Enter the number of voters: "); scanf("%d", &num_voters);